What is the approximate Larmor precessional frequency of a hydrogen proton in a static magnetic field of 0.5T?

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Multiple Choice

What is the approximate Larmor precessional frequency of a hydrogen proton in a static magnetic field of 0.5T?

Explanation:
The Larmor precessional frequency is calculated using the formula: \[ f = \frac{\gamma}{2\pi} \times B_0 \] where \( \gamma \) (the gyromagnetic ratio for a hydrogen proton) is approximately \( 42.58 \, \text{MHz/T} \), and \( B_0 \) is the strength of the magnetic field in Tesla. Given a magnetic field strength of 0.5T, substituting the values into the formula provides the following calculation: 1. First, compute \( \gamma \times B_0 \): \[ 42.58 \, \text{MHz/T} \times 0.5 \, \text{T} = 21.29 \, \text{MHz} \] 2. Convert this frequency into hertz (Hz): \[ 21.29 \, \text{MHz} = 21.29 \times 10^6 \, \text{Hz} \] 3. Divide by \( 2\pi \) to find the Larmor frequency: \[ f = \frac{21.29 \times 10^6}{2\pi} \

The Larmor precessional frequency is calculated using the formula:

[ f = \frac{\gamma}{2\pi} \times B_0 ]

where ( \gamma ) (the gyromagnetic ratio for a hydrogen proton) is approximately ( 42.58 , \text{MHz/T} ), and ( B_0 ) is the strength of the magnetic field in Tesla.

Given a magnetic field strength of 0.5T, substituting the values into the formula provides the following calculation:

  1. First, compute ( \gamma \times B_0 ):

[ 42.58 , \text{MHz/T} \times 0.5 , \text{T} = 21.29 , \text{MHz} ]

  1. Convert this frequency into hertz (Hz):

[ 21.29 , \text{MHz} = 21.29 \times 10^6 , \text{Hz} ]

  1. Divide by ( 2\pi ) to find the Larmor frequency:

[ f = \frac{21.29 \times 10^6}{2\pi} \

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